android自动循环筛选,使用具有重复结果的自定义筛选器完成Android自动完成_autocompletetextview_开发99编程知识库...

好的日子，我使用了可以過濾介面實現了這個自定義適配器，並在結果列表中獲得。public class SearchAutoCompleteAdapter extends BaseAdapter implements Filterable {

private ArrayList resultList;

List filteredProducts;

private LayoutInflater layoutInflater;

private Context context;

private int layout;

SearchAutoCompleteAPI searchautocomplete = new SearchAutoCompleteAPI();

public SearchAutoCompleteAdapter(Context context, int resource) {

super();

this.context = context;

this.layout = resource;

filteredProducts = new ArrayList();

resultList = new ArrayList();

}

@Override

public int getCount() {

return resultList.size();

}

@Override

public Object getItem(int index) {

return resultList.get(index);

}

@Override

public long getItemId(int position) {

return 0;

}

@Override

public View getView(int position, View convertView, ViewGroup parent) {

if (convertView == null) {

layoutInflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);

convertView = layoutInflater.inflate(layout, null);

}

TextView name = (TextView) convertView.findViewById(R.id.suggestion_text_id);

name.setText(resultList.get(position).getName());

return convertView;

}

@Override

public Filter getFilter() {

Filter filter = new Filter() {

@Override

protected FilterResults performFiltering(CharSequence constraint) {

FilterResults filterResults = new FilterResults();

List tempfilteredProducts = new ArrayList

filteredProducts.clear();

if (constraint!= null || constraint.length()> 0) {

tempfilteredProducts.clear();

tempfilteredProducts = searchautocomplete.autocomplete(constraint.toString());//webservice call

} else {

tempfilteredProducts = new ArrayList();

}

for (BaseAutocompleteItems items : tempfilteredProducts) {

if (items.getName().contains(constraint.toString())) {

filteredProducts.add(items);

}

}

filterResults.values = filteredProducts;

filterResults.count = filteredProducts.size();

return filterResults;

}

@Override

protected void publishResults (CharSequence constraint, FilterResults results){

resultList = (ArrayList)results.values;

if(results.count> 0) {

notifyDataSetChanged();

} else {

notifyDataSetInvalidated();

}

}

}

;

return filter;

}

}

如果我鍵入"叫喊"並按backspace鍵或者增加我的字元到，我得到相同的結果，因此arraylist最終會得到重複的條目。 在填充列表之前，我嘗試清除列表，但似乎沒有什麼工作。