如何用python统计数字跟随次数_python 统计数组中元素出现次数并进行排序的实例...

如下所示：

lis = [12,34,456,12,34,66,223,12,5,66,12,23,66,12,66,5,456,12,66,34,5,34]

def test1():

#进行去重

c = []

for i in lis:

if i not in c:

c.append(i)

#进行统计，生成二维列表

b = []

for i in c:

num = 0

for j in range(len(lis)):

if lis[j] == i:

num += 1

a = []

a.append(i)

a.append(num)

b.append(a)

# 排序算法，按出现次数进行降序排列

for i in range(len(b)):

for j in range(i,len(b)):

if b[i][1] < b[j][1]:

temp = b[i]

b[i] = b[j]

b[j] = temp

print(b)

def test2():

# set进行去重，进行统计生成二维列表

b = []

for i in list(set(lis)):

num = 0

for j in range(len(lis)):

if lis[j] == i:

num += 1

a = []

a.append(i)

a.append(num)

b.append(a)

# 排序算法，按出现次数进行降序排列

for i in range(len(b)):

for j in range(i,len(b)):

if b[i][1] < b[j][1]:

temp = b[i]

b[i] = b[j]

b[j] = temp

print(b)

def test3():

# 统计元素出现次数，元素为key，次数为value，生成字典

a = {}

for i in lis:

if i in a:

a[i] = a[i] + 1

else:

a[i] = 1

# 使用sorted对字典进行排序

b = sorted(a.items(),key=lambda item:item[1],reverse=True)

print(b)

def test4():

from collections import Counter

import operator

#进行统计

a = dict(Counter(lis))

#进行排序

b= sorted(a.items(), key=operator.itemgetter(1),reverse=True)

print(b)

if __name__ == '__main__':

test1()

test2()

test3()

test4()

输出结果如下：

[[12, 6], [66, 5], [34, 4], [5, 3], [456, 2], [223, 1], [23, 1]]

[[12, 6], [66, 5], [34, 4], [5, 3], [456, 2], [23, 1], [223, 1]]

[(12, 6), (66, 5), (34, 4), (5, 3), (456, 2), (23, 1), (223, 1)]

[(12, 6), (66, 5), (34, 4), (5, 3), (456, 2), (23, 1), (223, 1)]

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