What would be the fastest way to list the names of files from 1000+ directories and sub-directories?
EDIT;
The current code I use is:
import java.io.File;
public class DirectoryReader {
static int spc_count=-1;
static void Process(File aFile) {
spc_count++;
String spcs = "";
for (int i = 0; i < spc_count; i++)
spcs += " ";
if(aFile.isFile())
System.out.println(spcs + "[FILE] " + aFile.getName());
else if (aFile.isDirectory()) {
System.out.println(spcs + "[DIR] " + aFile.getName());
File[] listOfFiles = aFile.listFiles();
if(listOfFiles!=null) {
for (int i = 0; i < listOfFiles.length; i++)
Process(listOfFiles[i]);
} else {
System.out.println(spcs + " [ACCESS DENIED]");
}
}
spc_count--;
}
public static void main(String[] args) {
String nam = "D:/";
File aFile = new File(nam);
Process(aFile);
}
}
解决方案
This looks fine (Recursively going through the directory) The bottleneck will be all the file i/o you need to do, optimizing your Java will not show any real improvements.
本文介绍了一种有效处理大量目录及子目录中文件名的方法,通过递归遍历,讨论了可能的瓶颈并指出Java优化有限。关注如何在实际应用中提高文件搜索效率。
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