python字典的比较_python 对比两个字典的差异

实际遇到的问题逻辑很繁杂，就不全写了。最后是通过对比两个字典差异来解决的。找出两个字典的差异，可参考以下代码。

dict1 = {'a':1,'b':2,'c':3,'d':4}

dict2 = {'a':1,'b':2,'c':5,'e':6}

differ = set(dict1.items()) ^ set(dict2.items())

print(differ)

#所有差异

#输出:{('c', 3), ('e', 6), ('c', 5), ('d', 4)}

diff = dict1.keys() & dict2

diff_vals = [(k, dict1[k], dict2[k]) for k in diff if dict1[k] != dict2[k]]

print(diff_vals)

#相同key，不同value

#输出:[('c', 3, 5)]

其他参考：

a = {

"x":1,

"y":2,

"z":3

}

b = {

"x":1,

"w":11,

"z":12

}

print(a.items())

>>>dict_items([('x', 1), ('y', 2), ('z', 3)])

# 查看两个字典共有的key

print(a.keys() & b.keys())

>>>{'x', 'z'}

# 查看字典a 和字典b 的不共有的key

print(a.keys() ^ b.keys())

>>>{'y'}

# 查看在字典a里面而不在字典b里面的key

print(a.keys() - b.keys())

>>>{('x', 1)}

# 查看字典a和字典b相同的键值对

print(a.items() & b.items())

>>>{'w', 'y'}