txt文件处理数据

接着上一篇excel文件数据处理。本篇文章是处理txt文件

import os


def read_txt(name):
	start = 0
	end = 0
	an_niu = 0
	with open(name) as file:
		content = file.read()
		c_list = content.split('\n')

		for x in c_list:
			if not x:
				continue

			split_one = x.split(",")
			t,h,q = handle_data(split_one)
			if start == 0:
				if t:
					if h<1:
						h = 60+h
					start = h
					print("start:",start)
			if end == 0:
				if int(split_one[-1])==0:
					an_niu = 1
					pass
				if int(split_one[-1])==1 and start!=0 and an_niu == 1 and q<-100:
					if h<1:
						h = 60+h
					end = h
					print("end",end)
					an_niu = 0
	print("jieguo:",(end-start)*1000+0.5)
	print("*"*10)
	return (end-start)*1000+0.5

		

def handle_data(split_one):
	
	qian0 ,qian1 = split_one[0].split(" ")
	i = 0
	if int(qian1)>=5 or int(qian1)<=-5:
		q = qian0.split(":")[-1]
		i = float(q.split("]")[0])
		return 1,i,int(qian1)
	else:
		return 0,i,int(qian1)

def url_together(name):

	list_names = os.listdir(name)
	i = 0
	for list_n in list_names:

		if not "." in list_n:
			url_together(name+"/"+list_n)
		else:
			i += 1
			# 处理txt文件
	# print(i)
	if i>3:
		handle_txt(name)


def handle_txt(url_name):
	name_list = []
	names = os.listdir(url_name)
	for txt_name in names:
		if ".txt" in txt_name :
			name_list.append(txt_name)
	handle_vlues = []
	for name in name_list:
		v = read_txt(url_name+"/"+name)
		handle_vlues.append(int(v))
	print("="*30)
	print(url_name)
	handle_vlues.sort()
	# print("handle_vlues:",handle_vlues)
	print(max(handle_vlues))
	print(min(handle_vlues))
	handle_vlues = handle_vlues[1:-1]
	print(sum(handle_vlues)/len(handle_vlues))
	print("="*30)


if __name__ == '__main__':
	url_together("1次")

处理结果：算出变化时间。

遇到问题。时间是60进位。在读取是0了。所以我认为0是60所以解决一个问题。但是如果时间比较久。一个是0。另外一个进位到2。处理数据变很大。所以后期再更改。