select ajax加载数据,使用jquery和ajax加载select使用数据库值

var div_secretary = div_secretary + '

Secretary:';

var div_secretary = div_secretary + '';

var div_secretary = div_secretary + '-select-';

var div_secretary = div_secretary + '

我为获得数据库值jQuery函数是

$(function() {

var items = "";

$.getJSON("GetSecretaries.php", function(data) {

$.each(data, function(index, item) {

items += "" + item.SUBCODE + "";

});

$("#select_reviewer_secretary").html(items);

});

});

我为获得数据库的PHP代码是

$tac_Secretaries = array();

while ($result = oci_fetch_assoc($parse_Reviewer_test)) {

$tac_Secretaries[] = $result;

}

echo json_encode(array('value' => $tac_Secretaries));

当我加载页面我越来越喜欢 的JSON值

{"value":[{"CODE":"3621","SUBCODE":"4"},{"CODE":"1561","SUBCODE":"1"}]}

此处我如何将这些值加载到选择选项中。 由于事先

2014-09-26

Shahanas