itoa对应linux函数,Linux系统下关于函数itoa()?

#include

int atoi(const char *nptr);

long atol(const char *nptr);

long long atoll(const char *nptr);

long long atoq(const char *nptr);

linux下面没对应的好像，我man 没有查到.

给你直接找到一个实现，你放到自己代码里面就可以了

void itoa ( unsigned long val, char *buf, unsigned radix )

{

char *p; /* pointer to traverse string */

char *firstdig; /* pointer to first digit */

char temp; /* temp char */

unsigned digval; /* value of digit */

p = buf;

firstdig = p; /* save pointer to first digit */

do {

digval = (unsigned) (val % radix);

val /= radix; /* get next digit */

/* convert to ascii and store */

if (digval > 9)

*p++ = (char ) (digval - 10 + 'a '); /* a letter */

else

*p++ = (char ) (digval + '0 '); /* a digit */

} while (val > 0);

/* We now have the digit of the number in the buffer, but in reverse

order. Thus we reverse them now. */

*p-- = '\0 '; /* terminate string; p points to last digit */

do {

temp = *p;

*p = *firstdig;

*firstdig = temp; /* swap *p and *firstdig */

--p;

++firstdig; /* advance to next two digits */

} while (firstdig < p); /* repeat until halfway */

}