python怎么固定输入位数_使用python计数输入的位数

最新推荐文章于 2021-06-16 18:38:16 发布

最新推荐文章于 2021-06-16 18:38:16 发布 · 537 阅读

文章标签：

#python怎么固定输入位数

博客指出了一段Python代码在计算输入数字位数时出现的问题，当输入如10或11这样的两位数时，结果错误地返回325。问题在于使用了单斜线除法，导致了浮点数运算。解决方案是改用双斜线进行整数除法，确保每次迭代时正确地切掉数字的末尾一位。同时，注意到输入0的情况，0应该被视为一位数字。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

I am trying to count the number of digits of an input. However, whenever I input 10 or 11 or any two digit number, the output is 325. Why doesn't it work?

inputnumber = int(input())

countnumber = inputnumber

digitcount = 0

while countnumber > 0:

digitcount += 1

countnumber = countnumber/10

print(digitcount)

# result is 325 when input is 10 or 11

解决方案

Your error mainly happened here:

countnumber=countnumber/10

Note that you are intending to do integer division. Single-slash division in Python 3 is always "float" or "real" division, which yields a float value and a decimal part if necessary.

Replace it with double-slash division, which is integer division: countnumber = countnumber // 10. Each time integer division is performed in this case, the rightmost digit is cut.

You also have to watch out if your input is 0. The number 0 is considered to be one digit, not zero.