服务器监听客户端并响应,如何在java中监听和生成服务器端的客户端响应？

这是我的服务器端代码在Java监听1880端口，并从浏览器/ client.java代码在本地主机，它给连接拒绝error.I复制该服务器代码从网页。我不知道这是什么代码在做。如何在java中监听和生成服务器端的客户端响应？

import com.sun.net.httpserver.HttpExchange;

import com.sun.net.httpserver.HttpHandler;

import com.sun.net.httpserver.HttpServer;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

import java.io.OutputStream;

import java.io.PrintWriter;

import java.net.InetAddress;

import java.net.InetSocketAddress;

import java.net.ServerSocket;

import java.net.Socket;

public class ServerHandlingHttpRequest {

public void start() throws IOException

{

InetSocketAddress addr=new InetSocketAddress(1880);

System.out.println(addr.getPort());

System.out.println(addr.getAddress());

System.out.println(addr.getHostName());

System.out.println(addr.toString());

HttpServer server=HttpServer.create(addr,0);

server.createContext("/", new MyHandler());

server.setExecutor(null);

server.start();

System.out.println("Server Listening");

System.out.println(server.getAddress());

server.stop(60);

}

class MyHandler implements HttpHandler {

public void handle(HttpExchange t) throws IOException {

System.out.println("Request Arrived");

String response = "This is the response";

t.sendResponseHeaders(200, response.length());

OutputStream os = t.getResponseBody();

os.write(response.getBytes());

os.close();

}

}

public static void main(String[] args) throws IOException

{

ServerHandlingHttpRequest w=new ServerHandlingHttpRequest();

w.start();

}

}

2016-07-18

Badman

+0

你想用这个做什么？ –

+0

我想在端口1880上监听客户端请求并生成对该请求的响应。 –

+0

http://www.java2s.com/Tutorial/Java/0320__Network/LightweightHTTPServer.htm这是我从哪里复制和修改服务器端代码的链接。 –