python 累加器_python中的累加器

你想问的第一件事是当你print tries时，你得到了什么？

实际上，你会发现你总是得到1。在

因为，你没有增加。你没有添加，因为用户一直在猜测。在

通常，您可以为每个猜测编写tries = tries + 1。在tries = 1

while number != secretNumber:

if number > secretNumber:

print("Too high!")

tries = tries + 1 # here is the addition

number = input("Your guess: ")

number = int(number)

if number < secretNumber:

print("Too low!")

tries = tries + 1 # here is the addition

number = input("Your guess: ")

number = int(number)

while number == secretNumber:

print("You got it in",tries,"tries")

break

这个代码仍然有一些问题。第二个循环没有意义。循环听起来像循环。它一直在运行，直到满足某个条件或有人(你)打断它并告诉它退出。在

如果用户找到了号码，那么while number !- secretNumber将变成{}对吗？

它将退出第一个循环。因此，您可以跳过第二个循环并祝贺用户。在

另一个小问题是双if语句。

if语句代价高昂。计算机必须测试才能猜对。但无论哪种方式，都有不同的方法来处理多种情况。在

^{pr2}$

如果number > secretNumber是{}，那么理论上就不需要测试{}。它通过调整if .. elif .. else使代码更干净，逻辑上更合理import random

secretNumber = random.randint(1,100)

secretNumber = int(secretNumber)

print("Guess a number between 1 and 100!")

number = input("Your guess: ")

number = int(number)

tries = 1

while number != secretNumber:

if number > secretNumber:

print("Too high!")

tries = tries + 1 # here is the addition

number = input("Your guess: ")

number = int(number)

elif number < secretNumber:

print("Too low!")

tries = tries + 1 # here is the addition

number = input("Your guess: ")

number = int(number)

print("You got it in",tries,"tries")

# another way to print is

# print("You got it in %s tries" % tries)

# print("You got it in {t} tries".format(t=tries))

对于初学者，请使用print来帮助调试代码。在