根据一个什么玩意儿没听说过的定理,求的答案居然等价于n=1且众模与m的gcd作为输入的情况。。。
#include<iostream>
#include<cstdio>
#include<string.h>
#include<algorithm>
using namespace std;
int gcd(int a,int b)
{
if (b==0) return a;
return gcd(b,a%b);
}
int n,k,ar[100005];
int main()
{
scanf("%d%d",&n,&k);
int ans=k;
for (int i=1; i<=n; i++)
{
int x; scanf("%d",&x);
x=x%k;
if (x==0) ar[0]=1;
ans=gcd(ans,x);
}
for (long long i=(long long )ans; i<=k; i+=ans)
{
ar[i]=1;
}
if (ar[k]) ar[0]=1;
int sum=0;
for (int i=0; i<k; i++)
{
if (ar[i]) sum++;
}
printf("%d\n",sum);
ans=0;
for(int i=0;i<sum;i++){
while(!ar[ans])ans++;
printf("%d%c",ans,i==sum-1?'\n':' ');
ans++;
}
return 0;
}