#include <chrono>
using namespace chrono;
using namespace std;
steady_clock::time_point t1 = steady_clock::now();
/*time cost calc code */
steady_clock::time_point t2 = steady_clock::now();
duration<double> time_used = duration_cast<duration<double>>(t2 - t1);
cout<" time cost= "<< (time_used.count() * 1000) <<" ms."<<endl;
另外由于是std库,不需要再修改Cmake文件c++(linux)耗时计算
最新推荐文章于 2024-09-05 12:14:16 发布