65. Valid Number

本文介绍了一个用于判断给定字符串是否能表示一个有效数值的方法。该方法能够正确处理包括整数、浮点数及科学计数法在内的多种数值格式。

 

Validate if a given string is numeric.

Some examples:
"0" => true
" 0.1 " => true
"abc" => false
"1 a" => false
"2e10" => true

Note: It is intended for the problem statement to be ambiguous. You should gather all requirements up front before implementing one.

 

 

public bool IsNumber(string s) {
        int size = s.Length;
        if(size == 0) return false;
        int numindex = -1; 
        int dotindex = -1;
        int eindex = -1;//e index
        var possibleFirstChar = new List<char>(){'+','-','.'};
         var digits = new List<char>(){'0','1','2','3','4','5','6','7','8','9'};
        if(size == 1 && !digits.Contains(s[0])) return false;
        //remove spaces at the beginning till not ' '
        int start = 0;
        while(start< size && s[start] == ' ')
        {
            start++;
        }
        if(start == size) return false;
        //first letter just
        if(!possibleFirstChar.Contains(s[start]) && !digits.Contains(s[start])) return false;
        if(possibleFirstChar.Contains(s[start]))
        {
            if(s[start] == '.') { 
                dotindex = start;
            }
            start++;
        }
       
       
       
        int tempStart = start;
        int i =tempStart;
        for(;i<size && s[i] != ' ';i++)
        {
            if(s[i] == 'e') 
            {
                if(eindex >= 0 || numindex < 0) return false;// cannot have 2 'e' && must have digits before e
                eindex = i;
            }
            else if(s[i] == '.')
            {
                 if(eindex >= 0 || dotindex >= 0) return false; // cannot after '2' && can not have 2 '.'
                 dotindex = i;
            }
            else if(s[i] == '+' || s[i] == '-') //should be just after 'e'
            {
                if( eindex != i-1) return false;
            }
            else if(!digits.Contains(s[i])) return false; 
            else numindex = i;
        }
        //check whether we have extra spaces in the end
        if(i != size)
        {
            while(i<size)
            {
            if(s[i] !=' ') return false;
            i++;
            }
        }//blank at end
        if((dotindex==0 && eindex == 1)) return false;// such as .e12;
        if(numindex < 0 || numindex < eindex) return false;// such as . , e; 
        return true;
    }

 

转载于:https://www.cnblogs.com/renyualbert/p/5874186.html

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