java servlet获取参数乱码问题,高分 在线 急求 Servlet获取参数中文编码为乱码解决办法...

HTML code

String path = request.getContextPath();

String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";

// 获取目标视频文件名称

String seqid = RequestHelper.getNotNullString(request , "seqId");

//获取附件类型

KnowledgeShowDao temp = new KnowledgeShowDao();

String medianame = temp.att_MediaName(seqid);

String swfname="D:/UP/attachment/swf/"+medianame+".swf";

System.out.println("swfname值为：xxxxxxxxxssssssssssssxxxxxxx"+swfname);

%>

文件展示

pluginspage="http://www.macromedia.com/go/getflashplayer"

menu="true" loop="true" play="true"

type="application/x-shockwave-flash" style="z-index: -1;"

wmode="transparent" src="servlet/FileStreamReader?name="

width="800px" height="650px"

align="middle">