# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def countNodes(self, root):
if root is None:
return 0
return self.countNodes(root.left) +self.countNodes(root.right) + 1
leetcode222. 完全二叉树的节点个数
最新推荐文章于 2024-05-23 20:59:40 发布