满意答案
ptjgxe
2014.11.26
采纳率:46% 等级:9
已帮助:467人
1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950515253545556575859606162636465666768697071727374757677787980818283848586#includeint main(){ int i; int n; int size = 0; int num[20] = {0}; scanf("%d", &n); while(n > 0) { num[size++] = (n%10); n /= 10; } if(size == 0) { printf("zero\n"); return 0; } for(i = size-1; i >= 0; --i) { switch (num[i]) { case 0: { printf("zero"); break; } case 1: { printf("one"); break; } case 2: { printf("two"); break; } case 3: { printf("three"); break; } case 4: { printf("four"); break; } case 5: { printf("five"); break; } case 6: { printf("six"); break; } case 7: { printf("seven"); break; } case 8: { printf("eight"); break; } case 9: { printf("nine"); break; } } if(i != 0) { printf(","); } else { printf("\n"); } } return 0;}
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