[LeetCode] Binary Tree Inorder Traversal 中序排序

Given a binary tree, return the inorder traversal of its nodes' values.

For example:
Given binary tree {1,#,2,3},

   1
    \
     2
    /
   3

 

return [1,3,2].

Note: Recursive solution is trivial, could you do it iteratively?

confused what "{1,#,2,3}" means? > read more on how binary tree is serialized on OJ.

 

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---

    这题不难，直接写就通过了。

 

#include <iostream>
#include <vector>
using namespace std;

/**
 * Definition for binary tree
 */
struct TreeNode {
    int val;
    TreeNode *left;
    TreeNode *right;
    TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};

class Solution {
public:
    vector<int > ret;
    vector<int> inorderTraversal(TreeNode *root) {
        ret.clear();
        helpFun(root);
        return ret;
    }

    void helpFun(TreeNode * node)
    {
        if(node ==NULL) return ;
        helpFun(node->left);
        ret.push_back(node->val);
        helpFun(node->right);

    }
};

int main()
{
    return 0;
}

 

转载于:https://www.cnblogs.com/Azhu/p/4346002.html