CF218B：Airport（优先队列）

最新推荐文章于 2025-04-25 14:32:45 发布

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最新推荐文章于 2025-04-25 14:32:45 发布

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原文链接：http://www.cnblogs.com/junior19/p/6729992.html

本文探讨了n个乘客选择m架飞机的机票购买问题，每位乘客依次选择飞机并购票，票价等于所选飞机剩余座位数。文章提供了求解机场收益最大值与最小值的C++代码实现。

Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:

it is up to a passenger to choose a plane to fly on;
if the chosen plane has x (x > 0) empty seats at the given moment, then the ticket for such a plane costs x zlotys (units of Polish currency).

The only ticket office of the airport already has a queue of n passengers in front of it. Lolek and Bolek have not stood in the queue yet, but they are already wondering what is the maximum and the minimum number of zlotys the airport administration can earn if all npassengers buy tickets according to the conditions of this offer?

The passengers buy tickets in turn, the first person in the queue goes first, then goes the second one, and so on up to n-th person.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains m integers a1, a2, ..., am (1 ≤ ai ≤ 1000) — ai stands for the number of empty seats in the i-th plane before the ticket office starts selling tickets.

The numbers in the lines are separated by a space. It is guaranteed that there are at least n empty seats in total.

Output

Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly.

Examples

input
4 3
2 1 1

output
5 5

input
4 3
2 2 2

output
7 6

Note

In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.

In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd plane, the 3-rd person — to the 3-rd plane, the 4-th person — to the 1-st plane. The sum is minimized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 1-st plane, the 3-rd person — to the 2-nd plane, the 4-th person — to the 2-nd plane.

题意：n个乘客，m架飞机，每个乘客按顺序挑选一架飞机并买票，票价为他挑选的飞机的空位数，求航空公司可以赚取的最大价钱和最小价钱。

思路：略。

# include <iostream>
# include <cmath>
# include <cstdio>
# include <functional>
# include <queue>
using namespace std;
int main()
{
    int n, m, tmp, sum, sum2, a;
    while(~scanf("%d%d",&n,&m))
    {
        sum = sum2 = 0;
        priority_queue<int>Q;//大根堆
        priority_queue<int, vector<int>, greater<int> >P;//小根堆
        while(m--)
        {
            scanf("%d",&tmp);
            Q.push(tmp);
            P.push(tmp);
        }
        for(int i=0; i<n; ++i)
        {
            a = Q.top();
            sum += a;
            Q.pop();
            if(--a)
                Q.push(a);
        }
        for(int i=0; i<n; ++i)
        {
            a = P.top();
            sum2 += a;
            P.pop();
            if(--a)
                P.push(a);
        }
        printf("%d %d\n",sum, sum2);
    }
    return 0;
}

转载于:https://www.cnblogs.com/junior19/p/6729992.html