WPF下递归生成树形数据绑定到TreeView上

最新推荐文章于 2025-07-03 21:44:44 发布

转载最新推荐文章于 2025-07-03 21:44:44 发布 · 510 阅读

2 ·

CC 4.0 BY-SA版权

原文链接：https://yq.aliyun.com/articles/647022

文章标签：

#前端 #后端 #ViewUI

本文详细介绍了如何使用C#创建树形部门结构，并通过递归生成树形数据的方法来实现数据绑定。展示了如何利用TreeView控件和HierarchicalDataTemplate进行部门层级展示。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

最终效果图：（用于学习类的效果图片丑了点，看官莫怪）

新建窗体然后在前端适当位置插入如下代码：

  <TreeView x:Name="departmentTree"  Height="500" Width="500">
                            <TreeView.ItemTemplate>
                                <HierarchicalDataTemplate ItemsSource="{Binding Nodes}">
                                    <StackPanel>
                                        <TextBlock VerticalAlignment="Center" FontSize="14" Text="{Binding deptName}" Margin="2,0,0,0"></TextBlock>
                                    </StackPanel>
                                </HierarchicalDataTemplate>
                            </TreeView.ItemTemplate>
                        </TreeView>

后端代码：

  public class DepartmentModel
    {
       public List<DepartmentModel> Nodes { get; set; }
       public DepartmentModel()
        {
            this.Nodes = new List<DepartmentModel>();
            this.ParentId = 0;//主节点的父id默认为0
        }
       public int id { get; set; }//id
       public string deptName { get; set; }//部门名称
       public int ParentId { get; set; }//父类id
    }

public partial class TestWin : Window
    {
        public TestWin()
        {
            InitializeComponent();
            this.departmentTree.ItemsSource = getTrees(0, getDepts());//数据绑定
        }


        /// <summary>
        /// 获取部门列表--测试
        /// </summary>
        /// <returns></returns>
        public List<DepartmentModel> getDepts() {
            List<DepartmentModel> dplst = new List<DepartmentModel>(){
            new DepartmentModel(){id=1,deptName="主部门1",ParentId=0},
            new DepartmentModel(){id=2,deptName="主部门2",ParentId=0},
            new DepartmentModel(){id=3,deptName="主部门1_1",ParentId=1},
            new DepartmentModel(){id=4,deptName="主部门1_2",ParentId=1},
            new DepartmentModel(){id=5,deptName="主部门1_3",ParentId=1},
            new DepartmentModel(){id=6,deptName="主部门1_4",ParentId=1},
            new DepartmentModel(){id=7,deptName="主部门1_5",ParentId=1},
            new DepartmentModel(){id=8,deptName="主部门2_1",ParentId=2},
            new DepartmentModel(){id=9,deptName="主部门2_2",ParentId=2},
            new DepartmentModel(){id=10,deptName="主部门2_3",ParentId=2},
            new DepartmentModel(){id=11,deptName="主部门2_4",ParentId=2},
            new DepartmentModel(){id=12,deptName="主部门1_1_1",ParentId=3},
            new DepartmentModel(){id=13,deptName="主部门1_1_2",ParentId=3},
            new DepartmentModel(){id=14,deptName="主部门1_2_1",ParentId=4},
            new DepartmentModel(){id=15,deptName="主部门1_1_1_1",ParentId=12}
            };
            return dplst;
        }

        /// <summary>
        /// 递归生成树形数据
        /// </summary>
        /// <param name="delst"></param>
        /// <returns></returns>
        public List<DepartmentModel> getTrees(int parentid, List<DepartmentModel> nodes)
        {
            List<DepartmentModel> mainNodes = nodes.Where(x => x.ParentId == parentid).ToList<DepartmentModel>();
            List<DepartmentModel> otherNodes = nodes.Where(x => x.ParentId != parentid).ToList<DepartmentModel>();
            foreach (DepartmentModel dpt in mainNodes)
            {
                dpt.Nodes = getTrees(dpt.id,otherNodes);
            }
            return mainNodes;
        }

         
  
    }