开发：随笔记录之 判断list和map相等，并合并等问题

/**

• 根据特定规格，判断两个Map是否相等
  */
  private static boolean isEquals(Map<String, String> src, Map<String, String> dest, String[] samekey) {
  boolean equals = true;
  StringBuffer sbf_src = new StringBuffer();
  StringBuffer sbf_dest = new StringBuffer();
  for (int i = 0; i < samekey.length; i++) {
  sbf_src.append(src.get(samekey[i]));
  sbf_dest.append(dest.get(samekey[i]));
  }
  if (sbf_src.toString().equals(sbf_dest.toString())) {
  equals = true;
  } else {
  equals = false;
  }
  return equals;
  }

  /**

• 获得list中有没有相同的keyMap（待需找的map）<br>

• 如果找到则返回这个list和keyMap相同Map的下标，否则返回-1
  */
  private static int getEqualsMap(List<Map<String, String>> list, Map<String, String> keyMap, String[] samekey) {
  int equalsIndex = -1;
  for (int i = 0; i < list.size(); i++) {
  Map<String, String> tempMap = list.get(i);
  if (isEquals(tempMap, keyMap, samekey)) {
  equalsIndex = i;
  }
  }
  return equalsIndex;
  }

  /**

• 合并List中相同的Map
• @param list

• @return
  */
  public static List<Map<String, String>> combineList(List<Map<String, String>> list, String[] samekey,String combinekey) {
  List<Map<String, String>> retList = new ArrayList<Map<String, String>>();
  for (int i = 0; i < list.size(); i++) {
  Map<String, String> tempMap = list.get(i);
  int equalsIndex = getEqualsMap(retList, tempMap, samekey);
  if (-1 == equalsIndex) {
  retList.add(tempMap);
  } else {
  String custSrc = retList.get(equalsIndex).get(combinekey);
  int custSrcInt = Integer.parseInt(custSrc.substring(0, custSrc.length() - 1));
  String custTemp = tempMap.get(combinekey);
  int custTempInt = Integer.parseInt(custTemp.substring(0, custTemp.length() - 1));
  String destCust = (custSrcInt + custTempInt) + custSrc.substring(custSrc.length() - 1);
  retList.get(equalsIndex).put(combinekey, destCust);
  }
  }

   return retList;

  }

转载于:https://blog.51cto.com/13545923/2053397