Codeforces-930A Connected Components

传送门

 

n个点的树，以点1为根，告诉你经过每一秒，某顶点上的苹果会到达哪个顶点，且已知一个顶点每同时出现两个苹果就会碰撞消失（如2得0，如3得1），求有多少个苹果能到达顶点1

bfs求点深度

 

 1 #include <queue>
 2 #include <vector>
 3 #include <cstdio>
 4 #include <cstring>
 5 #include <algorithm>
 6 using namespace std;
 7 typedef long long LL;
 8 typedef pair<int, int> P;
 9 const int maxn = 1e5 + 10;
10 bool ans[maxn];
11 bool vis[maxn];
12 int n;
13 
14 vector<int> G[maxn];
15 
16 int main() {
17     scanf("%d", &n);
18     for (int i = 2; i <= n; i++) {
19         int u;
20         scanf("%d", &u);
21         G[u].push_back(i);
22     }
23     queue<P> que;
24     que.push(P(1, 0));
25     ans[0] = 1;
26     while (!que.empty()) {
27         P p = que.front(); que.pop();
28         int v = p.first;
29         int dis = p.second;
30         for (int i = 0; i < G[v].size(); i++) {
31             int tmp = G[v][i];
32             que.push(P(tmp, dis + 1));
33             ans[dis + 1] ^= 1;
34         }
35     }
36     int res = 0;
37     for (int i = 0; i <= n; i++) {
38         res += ans[i];
39     }
40     printf("%d\n", res);
41     return 0;
42 }

 

转载于:https://www.cnblogs.com/xFANx/p/8598243.html