Revit二次开发之“过滤得到某一标高上的所有风管”

风管的Level值为空，墙对应Level,风管对应ReferenceLevel

// 找到标高1上的所有风管
[Transaction(TransactionMode.Manual)]
[Regeneration(RegenerationOption.Manual)]
// [Journaling(JournalingMode.NoCommandData)]
public   class  cmdGetLevelDuct : IExternalCommand
{
     public  Result Execute(ExternalCommandData cmdData,  ref   string  message, ElementSet elements)
    {
        UIDocument uiDoc  =  cmdData.Application.ActiveUIDocument; // base.m_uiDoc
        Selection selection  =  uiDoc.Selection;

        Transaction ts  =   new  Transaction(uiDoc.Document,  " LevelDuct " );
        ts.Start();

        FilteredElementCollector collector  =   new  FilteredElementCollector(uiDoc.Document);
        collector.OfClass( typeof (Duct)).OfCategory(BuiltInCategory.OST_DuctCurves);

         foreach  (Element el  in  collector)
        {
            Duct duct  =  el  as  Duct;
             if  (duct.ReferenceLevel.Name  ==   " 标高 1 " )
                TaskDialog.Show( " title " , duct.Id.ToString());
        }

        ts.Commit();

         return  Result.Succeeded;
    }
}

from: http://revit.5d6d.com/thread-1204-1-1.html

转载于:https://www.cnblogs.com/greatverve/archive/2011/08/28/get-level-duct.html