【B - ECJTU_ACM 11级队员2012年暑假训练赛(2)】

棋盘游戏胜负判断
本文介绍了一个简单的棋盘游戏,玩家需将棋子从右上角移至下方,每次可以向下、向左或对角线移动。游戏由kiki开始,若双方都采取最佳策略,文章提供了判断胜利者的算法。
B - B
Time Limit:1000MS     Memory Limit:1000KB     64bit IO Format:%I64d & %I64u

Description

Recently kiki has nothing to do. While she is bored, an idea appears in his mind, she just playes the checkerboard game.The size of the chesserboard is n*m.First of all, a coin is placed in the top right corner(1,m). Each time one people can move the coin into the left, the underneath or the left-underneath blank space.The person who can't make a move will lose the game. kiki plays it with ZZ.The game always starts with kiki. If both play perfectly, who will win the game?
 

Input

Input contains multiple test cases. Each line contains two integer n, m (0<n,m<=2000). The input is terminated when n=0 and m=0.

 

Output

If kiki wins the game printf "Wonderful!", else "What a pity!".
 

Sample Input

5 3 5 4 6 6 0 0
 

Sample Output

What a pity! Wonderful! Wonderful!
 
 1 // Project name : B
 2 // File name    : main.cpp
 3 // Author       : Izumu
 4 // Date & Time  : Tue Jul 10 12:31:04 2012
 5 
 6 
 7 #include <iostream>
 8 #include <stdio.h>
 9 #include <string>
10 #include <cmath>
11 using namespace std;
12 
13 int main()
14 {
15     int n, m;
16     while (scanf("%d%d", &n, &m) != EOF && n + m)
17     {
18         if(n % 2 == 0 || m % 2 == 0)
19         {
20             printf("Wonderful!\n");
21         }
22         else
23         {
24             printf("What a pity!\n");
25         }
26     }
27     return 0;
28 }
29 
30 
31 // end 
32 // ism 

 

转载于:https://www.cnblogs.com/ismdeep/archive/2012/07/10/2584775.html

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值