HttpWebRequest 方式提交文件数据-以图片为例

最新推荐文章于 2019-10-15 16:56:09 发布

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最新推荐文章于 2019-10-15 16:56:09 发布

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文章标签： java 游戏

本文详细介绍了如何使用C#中的HTTP POST方法将文件上传到服务器，包括创建请求、设置参数、读取并发送文件内容，以及服务器端接收文件并保存的方法。

public void StartPing1(string pingURL)
        {
            HttpWebRequest request = (HttpWebRequest)WebRequest.Create(pingURL);
            FileStream fs = new FileStream(@"D:\111.jpg", FileMode.Open, FileAccess.Read);
            Byte[] bytes = new Byte[10240];
            request.Method = "POST";
            request.Proxy = null;
            //request.Headers.Add("XXX", "XXX");
            request.ContentType = "application/octet-stream";
            Stream dataStream = request.GetRequestStream();
            int count = fs.Read(bytes, 0, 10240);
            while (count != 0)
            {
                dataStream.Write(bytes, 0, count);
                count = fs.Read(bytes, 0, 10240);
            }
            fs.Close();
            dataStream.Close();
            try
            {
                HttpWebResponse response = (HttpWebResponse)request.GetResponse();
                StreamReader sr = new StreamReader(response.GetResponseStream(), Encoding.ASCII);
                string ret = sr.ReadToEnd();
                response.Close();
            }
            catch (System.Exception ex)
            {
                Console.WriteLine("!!!!!!ERROR!!!!!!!!" + ex.ToString() + "!!!!!!!!ERROR!!!!!!!!");
            }
        }

---下面是服务器端接收方法：

加载事件中：
/* 
            //StartPing1 方法 传送文件的
            System.Drawing.Image postImage = System.Drawing.Image.FromStream(Request.InputStream);
            System.Drawing.Bitmap bitmap_b = new System.Drawing.Bitmap(postImage);
            string Opath = @"D:\";
            string photoname = DateTime.Now.Ticks.ToString();
            bitmap_b.Save(Opath + "\\" + photoname + ".jpg", System.Drawing.Imaging.ImageFormat.Jpeg);
            Response.Write("<?xml version=\"1.0\"?><params><title>OK</title></params>");
             * */