Problem C: 平面上的点和线——Point类、Line类 (III)

本文介绍了一个使用C++实现的示例程序,通过定义Point和Line类来表示平面直角坐标系上的点和线段,并展示了如何创建这些对象以及它们的构造和析构过程。该程序还实现了对象的复制构造。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

Description

在数学上,平面直角坐标系上的点用X轴和Y轴上的两个坐标值唯一确定,两点确定一条线段。现在我们封装一个“Point类”和“Line类”来实现平面上的点的操作。
根据“append.cc”,完成Point类和Line类的构造方法和show()方法,输出各Line对象和Point对象的构造和析构次序。
接口描述:
Point::show()方法:按格式输出Point对象。
Line::show()方法:按格式输出Line对象。

Input

输入的第一行为N,表示后面有N行测试样例。每行为两组坐标“x,y”,分别表示线段起点和终点的x坐标和y坐标,两组坐标间用一个空格分开,x和y的值都在double数据范围内。

Output

输出为多行,每行为一条线段,起点坐标在前终点坐标在后,每个点的X坐标在前,Y坐标在后,Y坐标前面多输出一个空格,用括号包裹起来。输出格式见sample。
C语言的输入输出被禁用。

Sample Input

4 0,0 1,1 1,1 2,3 2,3 4,5 0,1 1,0

Sample Output

Point : (1, -2) is created. Point : (2, -1) is created. Point : (0, 0) is created. Point : (0, 0) ========================= Point : (0, 0) is created. Point : (1, 1) is created. Line : (0, 0) to (1, 1) is created. Line : (0, 0) to (1, 1) Line : (0, 0) to (1, 1) is erased. Point : (1, 1) is erased. Point : (0, 0) is erased. ========================= Point : (1, 1) is created. Point : (2, 3) is created. Line : (1, 1) to (2, 3) is created. Line : (1, 1) to (2, 3) Line : (1, 1) to (2, 3) is erased. Point : (2, 3) is erased. Point : (1, 1) is erased. ========================= Point : (2, 3) is created. Point : (4, 5) is created. Line : (2, 3) to (4, 5) is created. Line : (2, 3) to (4, 5) Line : (2, 3) to (4, 5) is erased. Point : (4, 5) is erased. Point : (2, 3) is erased. ========================= Point : (0, 1) is created. Point : (1, 0) is created. Line : (0, 1) to (1, 0) is created. Line : (0, 1) to (1, 0) Line : (0, 1) to (1, 0) is erased. Point : (1, 0) is erased. Point : (0, 1) is erased. ========================= Point : (1, -2) is copied. Point : (2, -1) is copied. Line : (1, -2) to (2, -1) is created. Point : (1, -2) is copied. Point : (0, 0) is copied. Line : (1, -2) to (0, 0) is created. Point : (2, -1) is copied. Point : (0, 0) is copied. Line : (2, -1) to (0, 0) is created. Point : (0, 0) is copied. Point : (2, -1) is copied. Line : (0, 0) to (2, -1) is created. Line : (1, -2) to (2, -1) Line : (1, -2) to (0, 0) Line : (2, -1) to (0, 0) Line : (0, 0) to (2, -1) Line : (0, 0) to (2, -1) is erased. Point : (2, -1) is erased. Point : (0, 0) is erased. Line : (2, -1) to (0, 0) is erased. Point : (0, 0) is erased. Point : (2, -1) is erased. Line : (1, -2) to (0, 0) is erased. Point : (0, 0) is erased. Point : (1, -2) is erased. Line : (1, -2) to (2, -1) is erased. Point : (2, -1) is erased. Point : (1, -2) is erased. Point : (0, 0) is erased. Point : (2, -1) is erased. Point : (1, -2) is erased.

HINT

Append Code

int main()
{
     char c;
     int num, i;
     double x1, x2, y1, y2;
     Point p(1, -2), q(2, -1), t;
     t.show();
     std::cin>>num;
     for (i = 1; i <= num; i++)
     {
         std::cout<< "=========================\n" ;
         std::cin>>x1>>c>>y1>>x2>>c>>y2;
         Line line(x1, y1, x2, y2);
         line.show();
     }
     std::cout<< "=========================\n" ;
     Line l1(p, q), l2(p, t), l3(q, t), l4(t, q);
     l1.show();
     l2.show();
     l3.show();
     l4.show();
}
 
代码
#include <iostream>
 
using namespace std;
 
class Point
{
     double x,y;
     friend class Line;
     public :
     Point( double xx=0, double yy=0):x(xx),y(yy)
     {
         cout<< "Point : (" <<x<< ", " <<y<< ") is created." <<endl;
     }
     ~Point()
     {
         cout<< "Point : (" <<x<< ", " <<y<< ") is erased." <<endl;
     }
     void show()
     {
         cout<< "Point : (" <<x<< ", " <<y<< ")" <<endl;
     }
     Point( const Point  & pl )
     {
         x=pl.x;
         y=pl.y;
         cout<< "Point : (" <<x<< ", " <<y<< ") is copied." <<endl;
     }
};
class Line
{
     Point p1,p2;
friend class Point;
     public :
         Line( double x1, double x2, double x3, double x4):p1(x1,x2),p2(x3,x4)
         {
             cout<< "Line : (" <<x1<< ", " <<x2<< ") to (" <<x3<< ", " <<x4<< ") is created." <<endl;
         }
         Line(Point &p,Point &q):p1(p),p2(q)
         {
             cout<< "Line : (" <<p1.x<< ", " <<p1.y<< ") to (" <<p2.x<< ", " <<p2.y<< ") is created." <<endl;
         }
         ~Line()
         {
             cout<< "Line : (" <<p1.x<< ", " <<p1.y<< ") to (" <<p2.x<< ", " <<p2.y<< ") is erased." <<endl;
         }
         void show()
         {
             cout<< "Line : (" <<p1.x<< ", " <<p1.y<< ") to (" <<p2.x<< ", " <<p2.y<< ")" <<endl;
         }
};
 
 
int main()
{
     char c;
     int num, i;
     double x1, x2, y1, y2;
     Point p(1, -2), q(2, -1), t;
     t.show();
     std::cin>>num;
     for (i = 1; i <= num; i++)
     {
         std::cout<< "=========================\n" ;
         std::cin>>x1>>c>>y1>>x2>>c>>y2;
         Line line(x1, y1, x2, y2);
         line.show();
     }
     std::cout<< "=========================\n" ;
     Line l1(p, q), l2(p, t), l3(q, t), l4(t, q);
     l1.show();
     l2.show();
     l3.show();
     l4.show();
}

转载于:https://www.cnblogs.com/go-ahead-TT/p/6724544.html

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值