【sql】交换位置 Exchange Seats

本文介绍了一个有趣的SQL挑战:为相邻的学生交换座位,并提供了一个具体的解决方案。该方案使用了SQL的UNION和CASE WHEN语句来实现学生座位的有效调整。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

问题:

Mary is a teacher in a middle school and she has a table seat storing students' names and their corresponding seat ids.

The column id is continuous increment.

Mary wants to change seats for the adjacent students.

Can you write a SQL query to output the result for Mary?

+---------+---------+
|    id   | student |
+---------+---------+
|    1    | Abbot   |
|    2    | Doris   |
|    3    | Emerson |
|    4    | Green   |
|    5    | Jeames  |
+---------+---------+

For the sample input, the output is:

+---------+---------+
|    id   | student |
+---------+---------+
|    1    | Doris   |
|    2    | Abbot   |
|    3    | Green   |
|    4    | Emerson |
|    5    | Jeames  |
+---------+---------+

Note:
If the number of students is odd, there is no need to change the last one's seat.

解决:

① 364ms

SELECT
    s.id,
    s.student
FROM
    (
        SELECT
            id - 1 AS id,
            student
        FROM
            seat
        WHERE
            (id % 2 = 0)
        UNION
            SELECT
                (CASE WHEN (cnt%2=1) AND id=cnt THEN id ELSE id + 1 END) AS id,
                student
            FROM
                seat,
                (select count(*) as cnt from seat) as seatcnt
            WHERE
                (id % 2 = 1)
    ) s
GROUP BY
    s.id ASC;

转载于:https://my.oschina.net/liyurong/blog/1605918

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值