<已解决>使用selector设置Button按下松开的样式以及 <item> tag requires a 'drawable' attribute or child tag defining a ...

最新推荐文章于 2021-05-25 13:59:22 发布

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最新推荐文章于 2021-05-25 13:59:22 发布

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文章标签：移动开发

原文链接：http://www.cnblogs.com/hitnoah/p/4698528.html

本文介绍了一种解决按钮在按下和释放状态时背景颜色切换问题的方法，并提供了有效的XML配置示例。

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<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
    <item android:color="@color/flatui_clouds" android:state_pressed="true" />
    <item android:color="@color/flatui_peter_river" />
</selector>

在Drawable/中定义了一个selector来进行按钮按下和松开的背景色变换,可是在运行时报错 <item> tag requires a 'drawable' attribute or child tag defining a drawable

解决方案:

把 android:background = "@drawable/button_anim" 改为 android:drawable= "@drawable/button_anim"

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更新: 无卵用

17:51更新

Why not simply use "drawable="@color/your_color" directly in your selector items instead? You don't need to define any shapes or any other files whatsoever, just have your color definitions in values/colors.xml (it's always good not to hardcode colors). – javaxian Apr 13 '14 at 13:37

<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
    <item android:drawable="@color/flatui_midnight_blue" android:state_pressed="true" />
    <item android:drawable="@color/flatui_concrete" />
</selector>