IntelliJ IDEA 创建 maven 项目-优快云博客

本文介绍了一个简单的Maven项目的搭建过程，包括项目结构的设置、部署步骤及Tomcat环境配置。通过示例代码详细展示了如何创建Servlet控制器、配置web.xml以及实现基本的表单提交与页面跳转。

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1. 新建一个maven项目

step 1

step 2

step 3

step 4

step 5

2. 设置自动导入

auto import

3. 项目目录结构

struct

4. 项目部署

step 1

step 2

step 3

step 4

step 5

step 6

step 7

5. 部署完得目录结构

new struct

6. 创建一个文件夹存放以后的包

step 1

step 2

7. 设置tomcat运行环境

step 1

step 2

step 3

step 4

step 5

8. 添加测试代码并完善web.xml

struct

DemoController.java

package com.test;

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;

@WebServlet("/myController")
public class DemoController extends HttpServlet {
    @Override
    protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
        doPost(req, resp);
    }

    @Override
    protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
        req.setCharacterEncoding("UTF-8");
        String name=req.getParameter("name");
        req.setAttribute("name",name);
        System.out.println(name);
        req.getRequestDispatcher("index.jsp").forward(req, resp);
    }

}

index.jsp

<%@ page contentType="text/html;charset=UTF-8" language="java" %>
<html>
<head>
    <title>Title</title>
</head>
<body>
<form action="myController" method="post">
    <input name="name">
    return:${name}
    <input value="提交" type="submit">
</form>
</body>
</html>

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
         version="3.1">

    <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>

</web-app>