模拟

#include <iostream>
using namespace std;
int main(){
    int n,i,j,num;
    num = 0;
    int b[100] = {100000};
    int count = 0;
    int counter = 0;
    cin>>n;
    int *a = new int(n);
    for (i = 0; i < n; i++) {
        cin>>a[i];
    }
    for (i = 0; i < n; i++) {
        for (j = i + 1; j < n; j++) {
            if (a[i] == a[j])
                count++;
            if(count >= counter){
                counter = count;
                b[i] = a[i];
            }
        }
        
    }
    j = b[0];
    for (i = 0; i < num; i++) {
        
        if (b[i] < j) {
            j = b[i];
        }
        //cout<<b[i]<<endl;
    }
    cout<<j<<endl;
    
    return 0;
    
    
}

 

转载于:https://www.cnblogs.com/MICE1024/p/5851391.html