dp[i]=sum{dp[j]} ,s[i...j-1]为出现过的单词,每次从s[i]开始查找全部出现的前缀s[i..j],前缀在Tire中存在则转移状态。


//#pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<cstring> #include<cstdlib> #include<algorithm> #include<iostream> #include<sstream> #include<cmath> #include<climits> #include<string> #include<map> #include<queue> #include<vector> #include<stack> #include<set> using namespace std; typedef long long ll; typedef pair<int,int> pii; #define pb(a) push_back(a) #define INF 0x1f1f1f1f #define lson idx<<1,l,mid #define rson idx<<1|1,mid+1,r #define PI 3.1415926535898 template<class T> T min(const T& a,const T& b,const T& c) { return min(min(a,b),min(a,c)); } template<class T> T max(const T& a,const T& b,const T& c) { return max(max(a,b),max(a,c)); } void debug() { #ifdef ONLINE_JUDGE #else freopen("d:\\in.txt","r",stdin); freopen("d:\\out1.txt","w",stdout); #endif } int getch() { int ch; while((ch=getchar())!=EOF) { if(ch!=' '&&ch!=' ')return ch; } return EOF; } struct TireNode { int flag; TireNode *next[26]; TireNode() { flag=0; for(int i=0;i<26;i++) next[i]=NULL; } }*root; int Insert(const char *s) { TireNode *p=root; for(int i=0;s[i]!='\0';i++) { int v=s[i]-'a'; if(p->next[v]==NULL) { p=p->next[v]=new TireNode; }else p=p->next[v]; } p->flag=1; return 0; } char str[300300]; int dp[300300]; int f(int k) { if(str[k]=='\0')return 1; if(dp[k]>=0)return dp[k]; int x=0; TireNode *p=root; for(int i=0;str[i+k]!='\0';i++) { int v=str[i+k]-'a'; if(p->next[v]==NULL)break; else p=p->next[v]; if(p->flag) { x=(x+f(i+k+1))%20071027; } } return dp[k]=x; } int del(TireNode *p) { for(int i=0;i<26;i++) { if(p->next[i]!=NULL) del(p->next[i]); } delete p; } int main() { int ca=0; while(scanf("%s",str)!=EOF) { root=new TireNode; int n; scanf("%d",&n); for(int i=1;i<=n;i++) { char s[110]; scanf("%s",s); Insert(s); } memset(dp,-1,sizeof(dp)); int num=f(0); printf("Case %d: %d\n",++ca,num); del(root); } return 0; }