[leetcode-682-Baseball Game]

最新推荐文章于 2020-11-29 19:31:13 发布

转载最新推荐文章于 2020-11-29 19:31:13 发布 · 138 阅读

CC 4.0 BY-SA版权

原文链接：http://www.cnblogs.com/hellowooorld/p/7586578.html

本文介绍了一个棒球得分计算器的设计与实现。该计算器接收一系列字符串指令输入，每条指令可以是整数得分、特殊操作（如加倍、加和、取消上一轮得分等），并最终返回所有有效轮次得分之和。文章提供了具体的示例来说明如何处理这些操作，并给出了一个简单的C++代码实现。

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You're now a baseball game point recorder.

Given a list of strings, each string can be one of the 4 following types:

Integer (one round's score): Directly represents the number of points you get in this round.
"+" (one round's score): Represents that the points you get in this round are the sum of the last two valid round's points.
"D" (one round's score): Represents that the points you get in this round are the doubled data of the last valid round's points.
"C" (an operation, which isn't a round's score): Represents the last valid round's points you get were invalid and should be removed.

Each round's operation is permanent and could have an impact on the round before and the round after.

You need to return the sum of the points you could get in all the rounds.

Example 1:

Input: ["5","2","C","D","+"]
Output: 15
Explanation: 
Round 1: You could get 5 points. The sum is: 5.
Round 2: You could get 2 points. The sum is: 7.
Operation 1: The round 2's data was invalid. The sum is: 5.  
Round 3: You could get 10 points (the round 2's data has been removed). The sum is: 15.
Round 4: You could get 5 + 10 = 15 points. The sum is: 30.

Example 2:

Input: ["5","-2","4","C","D","9","+","+"]
Output: 27
Explanation: 
Round 1: You could get 5 points. The sum is: 5.
Round 2: You could get -2 points. The sum is: 3.
Round 3: You could get 4 points. The sum is: 7.
Operation 1: The round 3's data is invalid. The sum is: 3.  
Round 4: You could get -4 points (the round 3's data has been removed). The sum is: -1.
Round 5: You could get 9 points. The sum is: 8.
Round 6: You could get -4 + 9 = 5 points. The sum is 13.
Round 7: You could get 9 + 5 = 14 points. The sum is 27.

Note:

The size of the input list will be between 1 and 1000.
Every integer represented in the list will be between -30000 and 30000.

思路：

模拟一下就好了。

int calPoints(vector<string>& ops) 
{
  if(ops.size()==0)return 0;
  vector<int>score;
  for(auto s:ops)
  {
    if(s == "C")score.pop_back();
    else  if(s == "D")score.push_back(score.back()*2);
    else  if(s == "+")score.push_back(score[score.size()-1]+score[score.size()-2]);
    else  
    {
     // int temp;
    //  stringstream ss(s);
    //  ss>>temp;
     // score.push_back(temp);
  　　score.push_back(atoi(s.c_str()));
    }
  }
  int sum = 0;
  for(auto a:score)cout<<a<<" ",sum+=a;
  return sum;  
}

转载于:https://www.cnblogs.com/hellowooorld/p/7586578.html