【xml]: Read XML with Namespace resolution using XLinq.XElement-优快云博客

本文详细介绍了如何使用C#的LINQ to XML库解析XML字符串，并通过XPath表达式定位到特定元素，进而获取该元素的子元素属性值。示例代码包括初始化XML字符串、定义命名空间、解析XML、定位所需元素以及提取属性值的过程。

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http://www.codeproject.com/KB/linq/xelementns.aspx

string myxml =
             @" <root>
                <one xmlns:a='http://rediff.com'>
                    <a:oneone  sequenceId= '11' xmlns:b='http://yahoo.com'>
                        <b:id>1</b:id>
                        <b:name></b:name>
                    </a:oneone>
                    <a:twotwo xmlns:b='http://orkut.com'>
                        <b:id>1</b:id>
                        <b:name></b:name>
                    </a:twotwo>
                </one>
              </root> ";

          XNamespace nsr = " http://rediff.com ";
          XNamespace nsy = " http://yahoo.com ";

            XElement elem = XElement.Parse(myxml);

             string t = elem.Element( " one ").Element(nsr + " oneone ").Element(nsy + " id ").Value;

            string sequenceId = elem.Element( " one ").Element(nsr + " oneone ").Attribute( " sequenceId ").Value;

           XDocument doc = new XDocument();
           doc = XDocument.Parse(myxml);

           XElement docElement = doc.Descendants(nsr + " oneone ").FirstOrDefault();

            string t1 = docElement.Element(nsr + " oneone ").Element(nsy + " id ").Value;

            string sequenceId1 = docElement.Element(nsr + " oneone ").Attribute( " sequenceId ").Value;