shell 脚本练习

为什么80%的码农都做不了架构师？>>>   

#!/bin/bash

read -t 30 -p "输入运算操作符:" oper

if [[ $oper != "+" &&  $oper != "-" && $oper != "*" && $oper != "/" ]]
then echo "oper is error"
exit 0
fi

read -t 30 -p "param1:" param1
read -t 30 -p "param2:" param2

case $oper in
"+") result=`expr $param1 + $param2`
;;
"-") result=`expr $param1 - $param2`
;;
"*") result=`expr $param1 \* $param2`
;;
"/") result=`expr $param1 / $param2`
;;
*) echo "error"
;;
esac
echo $result  

转载于:https://my.oschina.net/dongwt/blog/892546