POJ1426Find The Multiple[BFS]

Find The Multiple

Time Limit: 1000MS		Memory Limit: 10000K
Total Submissions: 27433		Accepted: 11408		Special Judge

Description

Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal digits.

Input

The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.

Output

For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.

Sample Input

2
6
19
0

Sample Output

10
100100100100100100
111111111111111111

Source

Dhaka 2002

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听说long long可以过就愉快地写了一个水bfs

从头搜索每一位

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <queue>
using namespace std;
const int N=1e6,INF=1e9;
typedef long long ll;
ll n;
queue<ll>q;
ll bfs(){
    ll x;
    while(!q.empty()) q.pop();
    q.push(1);
    while(!q.empty()){
        x=q.front();
        q.pop();
        if(x%n==0) return x;
        q.push(x*10);
        q.push(x*10+1);
    }
}
int main(){
    while(~scanf("%lld",&n)){
        if(n==0) break;
        printf("%lld\n",bfs());
    }
    return 0;
}