flask文件上传及访问显示的实现

使用Flask搭建文件上传服务

最新推荐文章于 2022-07-12 21:55:33 发布

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最新推荐文章于 2022-07-12 21:55:33 发布

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文章标签： python 后端

原文链接：https://my.oschina.net/u/2440318/blog/810085

2019独角兽企业重金招聘Python工程师标准>>>

import sys
reload(sys)
sys.setdefaultencoding("utf-8")
import os
from flask import Flask,url_for,render_template,request,url_for,redirect,send_from_directory
from werkzeug import secure_filename

UPLOAD_FOLDER='/home/alvy/'
ALLOWED_EXTENSIONS=set(['txt','pdf','png','jpg','jpeg','gif'])

app=Flask(__name__)

app.config['UPLOAD_FOLDER']=UPLOAD_FOLDER

def allowed_file(filename):
    return '.' in filename and filename.rsplit('.',1)[1] in ALLOWED_EXTENSIONS

@app.route('/',methods=['GET','POST'])
def upload_file():
    if request.method=='POST':
        file=request.files['file']
        if file and allowed_file(file.filename):
            filename=secure_filename(file.filename)
            file.save(os.path.join(app.config['UPLOAD_FOLDER'],filename))
            return redirect(url_for('upload_file'))
    return '''
    <!DOCTYPE html>
    <title>upload new file</title>
    <h1>upload file</h1>
    <form action="/" method="POST" enctype="multipart/form-data">
    <input type="file" name="file" />
    <input type="submit" value="upload" />
    </form>
    '''
@app.route('/uploads/<filename>')
def uploaded_file(filename):
    return send_from_directory(app.config['UPLOAD_FOLDER'],filename)

转载于:https://my.oschina.net/u/2440318/blog/810085