SQL: 判断给定日期值(或时间段)所在星期的星期一和星期天的日期

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最新推荐文章于 2024-08-13 02:15:38 发布

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本文介绍两个SQL函数：一是获取指定日期所在周的起止日期；二是根据起始和终止日期，列出其间所有完整的周及其起止日期。

最近报表要用到一项功能，需要把数据源根据记录发生日期所在的星期序列进行分组。因此就写了两个相关SQL Function进行调用。
一、给定一个日期值，求出此日期所在星期的星期一和星期天的日期数据
例如给定一个日期 2010-09-01，求出它所在星期的星期一是2010-08-30，星期天是2010-09-05

Function创建如下:

USE [MSSQL]
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[My_OneDay_GetWeekFirstAndEndDay](@tmpDate DATETIME)
RETURNS  @tmpTable TABLE(FirstDay DATETIME , EndDay DATETIME)
AS
BEGIN
    INSERT INTO @tmpTable
    SELECT a.FirstDay,b.EndDay FROM (
        SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 0) AS FirstDAy
    ) a
    LEFT JOIN (
        SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 6) AS EndDay
    ) b
    ON a.ID = b.ID
    RETURN
END

Function测试:

SELECT * from My_OneDay_GetWeekFirstAndEndDay('2010-09-01')

二、以上面单个日期搜索为基础，由用户输入两个参数，一个是开始日期，一个结束日期，根据这两个参数，求出在此时期段内的所有星期的星期一和星期天的日期表并排序。
例如开始日期是2011-09-01,结束日期是2011-10-06，我们就可以得到此星期表如下:
WeekOrder              FirstDay                                EndDay
1            2011-08-29 00:00:00.000 2011-09-04 00:00:00.000
2              2011-09-05 00:00:00.000 2011-09-11 00:00:00.000
3             2011-09-12 00:00:00.000 2011-09-18 00:00:00.000
4              2011-09-19 00:00:00.000 2011-09-25 00:00:00.000
5               2011-09-26 00:00:00.000 2011-10-02 00:00:00.000
6               2011-10-03 00:00:00.000 2011-10-09 00:00:00.000

Function创建如下:

USE [MSSQL]
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[MY_Range_GetWeekFirstAndEndDays](@tmpDateSTART DATETIME,@tmpDateEND DATETIME)
RETURNS  @tmpTable TABLE(WeekOrder INT,FirstDay DATETIME , EndDay DATETIME)
AS
BEGIN
DECLARE   @tmpDate   DATETIME
DECLARE   @index         INT
SET       @tmpDate=@tmpDateSTART
SET       @index=1
     WHILE     @tmpDate <=@tmpDateEND
        BEGIN
             INSERT INTO @tmpTable
                SELECT @index,a.FirstDay,b.EndDay FROM (
                    SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 0) AS FirstDAy) a
                LEFT JOIN (
                    SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 6) AS EndDay) b
                ON a.ID = b.ID

          SET   @tmpDate=DATEADD(DAY,7,@tmpDate)
          SET   @index=@index+1
         END
     RETURN
END

Function测试:

SELECT * from My_Range_GetWeekFirstAndEndDays('2011-09-01','2011-10-06')