[LeetCode] Shortest Word Distance

本文介绍了一种在一维单词列表中寻找两个指定单词间最短距离的算法。通过一次遍历列表,跟踪两个目标单词的最新位置,并计算它们之间的距离,从而高效地找到最短距离。

Problem Description:

Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list.

For example,
Assume that words = ["practice", "makes", "perfect", "coding", "makes"].

Given word1 = "coding"word2 = "practice", return 3.
Given word1 = "makes"word2 = "coding", return 1.

Note:
You may assume that word1 does not equal to word2, and word1 and word2 are both in the list.


The naive idea is very easy. But could you solve it in one-pass? Well, the one-pass code (taken from here) is rewritten in C++ as follows.

 1 class Solution {
 2 public:
 3     int shortestDistance(vector<string>& words, string word1, string word2) {
 4         int n = words.size(), idx1 = -1, idx2 = -1, dist = INT_MAX;
 5         for (int i = 0; i < n; i++) {
 6             if (words[i] == word1) idx1 = i;
 7             else if (words[i] == word2) idx2 = i;
 8             if (idx1 != -1 && idx2 != -1)
 9                 dist = min(dist, abs(idx1 - idx2));
10         }
11         return dist;
12     }
13 };

 

转载于:https://www.cnblogs.com/jcliBlogger/p/4704962.html

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