POJ 1573, Robot Motion

本文详细介绍了一种机器人在网格迷宫中导航的算法实现,通过解析输入指令,机器人能够找到出口或识别出循环路径。文章提供了完整的代码示例,展示了如何使用C++编程语言来跟踪机器人在网格上的移动,并判断其是否成功退出或陷入无限循环。

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模拟类


Description
A robot has been programmed to follow the instructions in its path. Instructions for the next direction the robot is to move are laid down in a grid. The possible instructions are

N north (up the page)
S south (down the page)
E east (to the right on the page)
W west (to the left on the page)

For example, suppose the robot starts on the north (top) side of Grid 1 and starts south (down). The path the robot follows is shown. The robot goes through 10 instructions in the grid before leaving the grid.

Compare what happens in Grid 2: the robot goes through 3 instructions only once, and then starts a loop through 8 instructions, and never exits.

You are to write a program that determines how long it takes a robot to get out of the grid or how the robot loops around.

 

Input
There will be one or more grids for robots to navigate. The data for each is in the following form. On the first line are three integers separated by blanks: the number of rows in the grid, the number of columns in the grid, and the number of the column in which the robot enters from the north. The possible entry columns are numbered starting with one at the left. Then come the rows of the direction instructions. Each grid will have at least one and at most 10 rows and columns of instructions. The lines of instructions contain only the characters N, S, E, or W with no blanks. The end of input is indicated by a row containing 0 0 0.

 

Output
For each grid in the input there is one line of output. Either the robot follows a certain number of instructions and exits the grid on any one the four sides or else the robot follows the instructions on a certain number of locations once, and then the instructions on some number of locations repeatedly. The sample input below corresponds to the two grids above and illustrates the two forms of output. The word "step" is always immediately followed by "(s)" whether or not the number before it is 1.

 

Sample Input
3 6 5
NEESWE
WWWESS
SNWWWW
4 5 1
SESWE
EESNW
NWEEN
EWSEN
0 0 0

 

Sample Output
10 step(s) to exit
3 step(s) before a loop of 8 step(s)

 

Source
Mid-Central USA 1999


 

//  POJ1573.cpp : Defines the entry point for the console application.
//

#include 
< iostream >
using   namespace  std;

int  main( int  argc,  char *  argv[])
{
    
int  width, height, ep;
    
char  ins[ 11 ][ 11 ];
    
char  mark[ 11 ][ 11 ];
    
int  x, y, steps, loop, status;
    
while  (cin  >>  height  >>  width  >>  ep  &&  width  &&  height  &&  ep)
    {
        steps 
=   1 ;
        loop 
=   0 ;
        x 
=  ep  -   1 ; y  =   0 ;
        status 
=   0 // 0 normal, 1 out, 2 loop
        memset(mark,  0 sizeof (mark));
        mark[y][x] 
=   1 ;
        
for  ( int  i  =   0 ; i  <  height;  ++ i)
            cin 
>>  ins[i];

        
while  ( true )
        {
            
switch (ins[y][x])
            {
            
case   ' N ' : -- y; break ;
            
case   ' S ' : ++ y; break ;
            
case   ' E ' : ++ x; break ;
            
case   ' W ' : -- x; break ;
            }
            
if  ( y  <   0   ||  y  >=  height  ||  x  <   0   ||  x  >= width)
            {
                status 
=   1 ;
                
break ;
            }

            
++ mark[y][x];
            
if  (mark[y][x]  ==   3 )
            {
                status 
=   2 ;
                
break ;
            }

            
if  (mark[y][x]  ==   1 ++ steps;
            
else   if  (mark[y][x]  ==   2 ) ++ loop;
        }

        
if  (status  ==   1 ) cout  <<  steps  << "  step(s) to exit\n " ;
        
else   if  (status  ==   2 ) cout  <<  steps  -  loop  << "  step(s) before a loop of  "   <<  loop  << "  step(s)\n " ;
    }
    
return   0 ;
}

转载于:https://www.cnblogs.com/asuran/archive/2009/09/29/1576078.html

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