UVa_488 - Triangle Wave

最新推荐文章于 2016-08-20 18:16:42 发布

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最新推荐文章于 2016-08-20 18:16:42 发布

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本文介绍了一个简单的程序，用于根据指定的振幅和频率生成三角波形。输入包括振幅和频率两个整数，程序输出对应数量的三角波形，每个波形的高度等于振幅值。波形由每行的整数组成，表示该行的高度。

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Triangle Wave

In this problem you are to generate a triangular wave form according to a specified pair of Amplitude and Frequency.

Input and Output

The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive inputs.

Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; the second integer is the Frequency.

For each test case, the output must follow the description below. The outputs of two consecutive cases will be separated by a blank line.

For the output of your program, you will be printing wave forms each separated by a blank line. The total number of wave forms equals the Frequency, and the horizontal ``height'' of each wave equals the Amplitude. The Amplitude will never be greater than nine.

The waveform itself should be filled with integers on each line which indicate the ``height'' of that line.

NOTE: There is a blank line after each separate waveform, excluding the last one.

Sample Input

Sample Output

View Code

#include <stdio.h>
int main()
{
int a, f, n;
int i, j;
    scanf("%d",&n);
while(n--)
    {
        scanf("%d",&a);
        scanf("%d",&f);
while(f--)
        {
for(i =1; i <= a; i++)
            {
for(j =0; j < i; j++)
                    printf("%d",i);
                 printf("\n");
            }
for(i = a-1; i >=1; i--)
            {
for(j =0; j < i; j++)
                    printf("%d",i);
                printf("\n");
            }
if(f)
                printf("\n");
        }
if(n)
            printf("\n");
    }
return0;
}