Cluster by

2019独角兽企业重金招聘Python工程师标准>>>

I recently gave a "mental challenge" in form of writing a clusterBy function that take a list and a function that calculates some result on every element of the list; the result of the clusterBy function should be a list of clusters. A cluster is a list of elements from the original list for which the clustering function returns the same value.

As an example, let's cluster a list of strings using the length of the string. In other words, ("one", "two", "three", "eleven", "twelve") should cluster to (List(three), List(twelve, eleven), List(two, one)).
We create three clusters: one for strings of length 3, one for strings of length 5 and one for strings of length 6. We then add the values to the appropriate cluster.
I had a go at implementing the code in Scala, and here's my first attempt. For historical purposes, and to show different approaches, I will keep returning to this post as I discover better implementations.

def clusterBy[A, B](l: Iterable[A])(f: A => B) =
  l.map(e => (f(e), e))./:(new HashMap[B, List[A]])(
    (res, cur) => res + ((cur._1, cur._2 :: res.getOrElse(cur._1, Nil)))
  ).values

Calling clusterBy(List("one", "two", "three", "eleven", "twelve"))(_.length) returns MapLike(List(three), List(twelve, eleven), List(two, one)). Success! So, what did I do? Let's explore each step of the way.
First, the concepts. We need to go through all elements of the given container and calculate the value of f for the elements. This gives us element -> f(element) container. We then need to group the pairs into a new structure with elements that contain f(element) -> (element1, element2, …, elementn). The result of the entire operation are the values of the grouped by container.

Onwards to the code, then.
We start with def clusterBy[A, B](l: Iterable[A])(f: A => B), which defines a function called clusterBy with two generic types A and B--that's the def clusterBy[A, B] bit. The function is curried--it takes two parameter lists. The first parameter list includes just one element, l: Iterable[A]. This is the source data, a container that holds source values of type A. The second parameter list includes just one element, f: A => B, which is a function that takes the element type (A) and maps it to some other type B.
The next line starts with l.map(e => (f(e), e)) which maps the elements of the parameter l into some other container that contains tuples made up of the mapped element and the original element. So, if l were List("x", "xy"), l.map(e => (f(e), e)) would return List((1, "x"), (2, "xy")).
Next, we fold left the returned list using empty map (that's the new HashMap[B, List[A]]--our grouped by container). The fold operation (working on the tuples) takes the first element of the tuple as the key in the group by map and the second element of the tuple is the value that should be added to the value associated with the key in the map. The line

(res, cur) => res + ((cur._1, cur._2 :: res.getOrElse(cur._1, Nil)))

receives the res running result of the fold left operation (the map) and cur, which is every (f(element) -> element) pair. The operation returns a map that is constructed by putting (in the old Java speak) a pair where the key is cur._1 and the value is either a new list with just cur._2 in it, or a list constructed by adding cur._2 to the existing list.
Finally, the result of the entire operation are the values of the constructed group by container.

转载于:https://my.oschina.net/u/2935389/blog/1475433