C#保留小数位的方法集合

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System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo(); provider.NumberDecimalDigits =intDecLength; //要设定的小数位数 double strCashAmt=Convert.ToDouble( this .txtCashAmt.Text); //先把控件內的值转成double    this .txtCashAmt.Text = strCashAmt.ToString( "N" ,provider); //再利用ToString函数格式化小数位数        //2.保留N位,四舍五入 .    decimal d= decimal .Round( decimal .Parse( "0.55555" ),2);        //3.保留N位四舍五入    Math.Round(0.55555,2)        //4,保留N位四舍五入 double dbdata = 0.55555; string str1 = dbdata.ToString( "f2" ); //fN 保留N位，四舍五入        //5.保留N位四舍五入    string result = String.Format( "{0:N2}" , 0.55555); //2位    string result = String.Format( "{0:N3}" , 0.55555); //3位        //6. 保留N位四舍五入 (不错)    double s=0.55555; result=s.ToString( "#0.00" ); //点后面几个0就保留几位        //C#下如果显示保留小数位数，及百分号的解决方法:    //1、用NumberFormatInfo类来解决: System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo();    provider.PercentDecimalDigits = 2; //小数点保留几位数. provider.PercentPositivePattern = 2; //百分号出现在何处. double result = ( double )1 / 3; //一定要用double类型. Response.Write(result.ToString( "P" , provider));    //2、用toString方法.: public string getRate( double hcount, double task) { string rValue; string temp = "" ;    if (task == 0) { task = 1; }    double db = (hcount / task) * 100;    if (hcount >= task) { rValue = "100%" ; } else { rValue = db.ToString( "#0.#0" ) + "%" ; } return rValue; }    string str1 = String.Format( "{0:N1}" ,56789); //result: 56,789.0 string str2 = String.Format( "{0:N2}" ,56789); //result: 56,789.00 string str3 = String.Format( "{0:N3}" ,56789); //result: 56,789.000 string str8 = String.Format( "{0:F1}" ,56789); //result: 56789.0 string str9 = String.Format( "{0:F2}" ,56789); //result: 56789.00 string str11 =(56789 / 100.0).ToString( "#.##" ); //result: 567.89 string str12 =(56789 / 100).ToString( "#.##" ); //result: 567

转载于:https://www.cnblogs.com/wifi/articles/2482312.html