Problem B
Peter’s Smokes
Input: standard input
Output: standard output
Time Limit: 4 seconds
Memory Limit: 32 MB
Peter has n cigarettes. He smokes them one by one keeping all the butts. Out of k > 1 butts he can roll a new cigarette.
How many cigarettes can Peter have?
Input
Input is a sequence of lines. Each line contains two integer numbers giving the values of n and k. The input is terminated by end of file.
Output
For each line of input, output one integer number on a separate line giving the maximum number of cigarettes that Peter can have.
Sample Input
4 3
10 3
100 5
Sample Output
5
14
124
#include"stdio.h" int main() { long n,k,s,m;//n为烟,m为烟头,k为换率,s为总数; while(scanf("%ld%ld",&n,&k)!=EOF) {s=0; s+=n; m=n; while(m>=k) {n=m/k; s+=n; m=m%k+n; } printf("%ld\n",s); } return 0; }
本文提供了一道关于如何利用剩余烟蒂制作新香烟的算法题解答。问题描述为:Peter有n支香烟,每抽完k支可以制作一支新的香烟,求Peter最多能有多少支香烟。通过递归计算剩余烟蒂并累加制作的新香烟数量,给出了完整的C语言程序实现。
1888

被折叠的 条评论
为什么被折叠?



