tomcat健康检查监控脚本

最新推荐文章于 2021-04-21 19:28:54 发布

weixin_34005042

最新推荐文章于 2021-04-21 19:28:54 发布

阅读量1.1k

点赞数

CC 4.0 BY-SA版权

文章标签： java awk

原文链接：http://www.cnblogs.com/franjia/p/6856510.html

本文介绍了一个用于自动监控并重启Tomcat服务的Shell脚本。该脚本通过检查Tomcat进程是否存在及页面响应状态来判断是否需要重启服务，并能够记录错误日志。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

#!/bin/sh
#自动监控tomcat脚本并且执行重启操作
#获取tomcat_ID
TomcatID=`ps -ef|grep tomcat|grep -v "grep"|grep -v "monitor_tomcat"|awk '{print $2}'`
Tomcatbag=`ls /usr/local/apache-tomcat-7.0.42/webapps -t |head -1`
#tomcat启动程序
StartTomcat=/home/deployer/scripts/monitor_restart.sh
TomcatCache=/usr/local/apache-tomcat-7.0.42/work/
# 定义要监控的页面地址
#积分 WebUrl=http://127.0.0.1:8080/integral/health/check
WebUrl=http://127.0.0.1:8080/$Tomcatbag/healthCheck/verify
# 日志输出
GetPageInfo=/home/deployer/scripts/monitor_logs/error_$(date +'%F').log
TomcatMonitorLog=/home/deployer/scripts/monitor_logs/TomcatMonitor_$(date +'%F').log

Monitor()
    {
      echo "[info]开始监控tomcat...[$(date +'%F %H:%M:%S')]"
      if [[ $TomcatID ]];then
        echo "[info]当前tomcat进程ID为:$TomcatID,检测页面..."
        TomcatServiceCode=$(curl -s -o $GetPageInfo -m 10 --connect-timeout 30 $WebUrl -w %{http_code})
        echo $TomcatServiceCode
        if [ $TomcatServiceCode -eq 200 ];then
            echo "[info]页面返回码为$TomcatServiceCode,tomcat启动成功,测试页面正常......"
        else
            echo "[error]tomcat页面出错,请注意......状态码为$TomcatServiceCode,错误日志已输出到$GetPageInfo"
            echo "[error]页面访问出错,开始重启tomcat"
            kill -9 $TomcatID
            sleep 3
            rm -rf $TomcatCache
            $StartTomcat
        fi
      else
        echo "[error]tomcat进程不存在!tomcat开始自动重启..."
        echo "[info]$StartTomcat,请稍候......"
        rm -rf $TomcatCache
        $StartTomcat
      fi
      echo "------------------------------"
   }

Monitor>>$TomcatMonitorLog
cd /home/deployer/scripts/monitor_logs
find . -maxdepth 2 -mtime +5 -name "*.log" -exec rm -rf {} \;