mysql报Table 'XXX' is specified twice, both as a target for 'UPDATE'....

最新推荐文章于 2025-04-03 21:25:32 发布

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最新推荐文章于 2025-04-03 21:25:32 发布

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原文链接：https://my.oschina.net/u/3081965/blog/1613824

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2019独角兽企业重金招聘Python工程师标准>>>

今天在执行这样一条语句

update CarModel set status=0 where id in(
select m.id from CarModel m where type='cs' and NOT EXISTS(select c.modelId from Car c where c.modelId=m.id))

mysql跑出来这样子一个错误

Table 'CarModel' is specified twice, both as a target for 'UPDATE' and as a separate source for data

改成这个就可以了

update CarModel set status=0 where id in(
select * from (select m.id from CarModel m where type='cs' and NOT EXISTS(select c.modelId from Car c where c.modelId=m.id)) as temp)

转载于:https://my.oschina.net/u/3081965/blog/1613824