问题:
配置了JdbcPagingItemReader用于读取数据,在启动时报如下Exception
Caused by: java.sql.SQLException: 列名无效
at oracle.jdbc.driver.OracleStatement.getColumnIndex(OracleStatement.java:3711)
at oracle.jdbc.driver.OracleResultSetImpl.findColumn(OracleResultSetImpl.java:2806)
at oracle.jdbc.driver.OracleResultSet.getObject(OracleResultSet.java:462)
at weblogic.jdbc.wrapper.ResultSet_oracle_jdbc_driver_OracleResultSetImpl.getObject(Unknown Source)
at org.springframework.batch.item.database.JdbcPagingItemReader$PagingRowMapper.mapRow(JdbcPagingItemReader.java:333)
at org.springframework.jdbc.core.RowMapperResultSetExtractor.extractData(RowMapperResultSetExtractor.java:93)
at org.springframework.jdbc.core.RowMapperResultSetExtractor.extractData(RowMapperResultSetExtractor.java:60)
at org.springframework.jdbc.core.JdbcTemplate$1.doInPreparedStatement(JdbcTemplate.java:708)
at org.springframework.jdbc.core.JdbcTemplate.execute(JdbcTemplate.java:644)
... 54 more
原因:
OraclePagingQueryProvider的配置中,sortKeys中的key值加了表名的替代名,即(c.),导致在代码rs.getObject(sortKey.getKey()),无法识别key对应的列
<bean id="myQueryProvider"
class="org.springframework.batch.item.database.support.OraclePagingQueryProvider">
<property name="selectClause" value="c.col1,'T' as type" />
<property name="fromClause" value="mytable c" />
<property name="whereClause" value="col2 = :param1" />
<property name="sortKeys">
<map>
<entry key="c.col1" value="ASCENDING"/>
</map>
</property>
</bean>
解决:
c.col1修改为col1即可