CodeForces 478C Table Decorations

本文解析了一道关于使用不同颜色气球装饰桌子的算法题。题目要求使用红、绿、蓝三种颜色的气球,每张桌子装饰三个不同颜色的气球,最大化可以装饰的桌子数量。通过分析输入的每种颜色气球的数量,给出最大装饰桌子数的解决方案。

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Table Decorations
Time Limit:1000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u

Description

You have r red, g green and b blue balloons. To decorate a single table for the banquet you need exactly three balloons. Three balloons attached to some table shouldn't have the same color. What maximum number t of tables can be decorated if we know number of balloons of each color?

Your task is to write a program that for given values rg and b will find the maximum number t of tables, that can be decorated in the required manner.

Input

The single line contains three integers rg and b (0 ≤ r, g, b ≤ 2·109) — the number of red, green and blue baloons respectively. The numbers are separated by exactly one space.

Output

Print a single integer t — the maximum number of tables that can be decorated in the required manner.

Sample Input

Input
5 4 3
Output
4
Input
1 1 1
Output
1
Input
2 3 3
Output
2

Hint

In the first sample you can decorate the tables with the following balloon sets: "rgg", "gbb", "brr", "rrg", where "r", "g" and "b" represent the red, green and blue balls, respectively.

 1 #include <stdio.h>
 2 #include <string.h>
 3 #include <algorithm>
 4 using namespace std;
 5 int main()
 6 {
 7     long long r,g,b;
 8     long long a[10];
 9     long long i,j,k;
10     while(scanf("%I64d %I64d %I64d",&r,&g,&b)!=EOF)
11     {
12         long long s=0;
13         a[1]=r,a[2]=g,a[3]=b;
14         sort(a+1,a+4);
15         s=s+a[1];
16         long long q=(a[2]+a[3])-a[1]*2,o;
17         o=q/3;
18         if(o<=a[2])
19             s=s+o;
20         else
21             s=s+a[2];
22         printf("%I64d\n",s);
23     }
24     return 0;
25 }
View Code

 

转载于:https://www.cnblogs.com/cyd308/p/4771534.html

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