hdu 1001 Sum Problem-优快云博客

本文介绍了一个简单的HDOJ题目，任务是计算从1到n的整数之和。通过示例输入和输出展示了如何使用C语言解决这个问题，并提供了一份完整的代码实现。

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Sum Problem

Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 487269 Accepted Submission(s): 123725

Problem Description

Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.

Input

The input will consist of a series of integers n, one integer per line.

Output

For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.

Sample Input

1 100

Sample Output

1 5050

水题不加题解可以直接看明白的

 1 #include<stdio.h>
 2 #include<cmath>
 3 #include<iostream>
 4 #include<cstring>
 5 #include<algorithm>
 6 #include<queue>
 7 using namespace std;
 8 int main ()
 9 {
10     long int n,i,sum;
11     while(scanf("%ld",&n)!=EOF)
12     { 
13      sum=0;
14      for(i=1;i<=n;i++)
15      {
16       sum+=i;
17      }
18      printf("%ld\n",sum);
19      printf("\n");
20     }
21 return 0;
22 }