how to download image from any web page in java 下载图片

http://stackoverflow.com/questions/5882005/how-to-download-image-from-any-web-page-in-java

 

(throws IOException) Image image = null; try { URL url = new URL("http://www.yahoo.com/image_to_read.jpg"); image = ImageIO.read(url); } catch (IOException e) { } See javax.imageio package for more info. That's using the AWT image. Otherwise you could do: URL url = new URL("http://www.yahoo.com/image_to_read.jpg"); InputStream in = new BufferedInputStream(url.openStream()); ByteArrayOutputStream out = new ByteArrayOutputStream(); byte[] buf = new byte[1024]; int n = 0; while (-1!=(n=in.read(buf))) { out.write(buf, 0, n); } out.close(); in.close(); byte[] response = out.toByteArray(); And you may then want to save the image so do: FileOutputStream fos = new FileOutputStream("C://borrowed_image.jpg"); fos.write(response); fos.close(); share improve this answer edited Jul 6 '13 at 2:01 Community ♦ 1 answered  May 4 '11 at 10:32 planetjones 7,78912844

2   For Java7 modify the code snippet to use the try-with-resources statement, seedocs.oracle.com/javase/tutorial/essential/exceptions/… – Gonfi den Tschal Jul 7 '13 at 1:18 add a comment

up vote 6down vote	You are looking for a web crawler. You can use JSoup to do this, here is basic example share improve this answer answered  May 4 '11 at 10:31 Jigar Joshi 148k20236309
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up vote 5down vote

It works for me) URL url = new URL("http://upload.wikimedia.org/wikipedia/commons/9/9c/Image-Porkeri_001.jpg"); InputStream in = new BufferedInputStream(url.openStream()); OutputStream out = new BufferedOutputStream(new FileOutputStream("Image-Porkeri_001.jpg")); for ( int i; (i = in.read()) != -1; ) { out.write(i); } in.close(); out.close(); share improve this answer edited Apr 15 '14 at 21:22     answered  Apr 15 '14 at 21:11 G.F. 13828

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up vote 3down vote	If you want to save the image and you know its URL you can do this: try(InputStream in = new URL("http://example.com/image.jpg").openStream()){ Files.copy(in, Paths.get("C:/File/To/Save/To/image.jpg")); } You will also need to handle the IOExceptions which may be thrown. share improve this answer answered  Sep 9 '15 at 6:15 Alex 4,95511528
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up vote 0down vote

The following code downloads an image from a direct link to the disk into the project directory. Also note that it uses try-with-resources. import java.io.BufferedInputStream; import java.io.BufferedOutputStream; import java.io.File; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.io.OutputStream; import java.net.MalformedURLException; import java.net.URL; import org.apache.commons.io.FilenameUtils; public class ImageDownloader { public static void main(String[] arguments) throws IOException { downloadImage("https://upload.wikimedia.org/wikipedia/commons/7/73/Lion_waiting_in_Namibia.jpg", new File("").getAbsolutePath()); } public static void downloadImage(String sourceUrl, String targetDirectory) throws MalformedURLException, IOException, FileNotFoundException { URL imageUrl = new URL(sourceUrl); try (InputStream imageReader = new BufferedInputStream( imageUrl.openStream()); OutputStream imageWriter = new BufferedOutputStream( new FileOutputStream(targetDirectory + File.separator + FilenameUtils.getName(sourceUrl)));) { int readByte; while ((readByte = imageReader.read()) != -1) { imageWriter.write

转载于:https://www.cnblogs.com/donaldlee2008/p/5281965.html