冒泡排序

li=[11,33,4,208,22,89,182,32,69,358,222]

for j in range(1,len(li)):#为外层循环次数
    for i in range(len(li)-j):
        current_value=li[i]
        next_value=li[i+1]
        if current_value > next_value:
            temp=li[i]
            li[i]=li[i+1]
            li[i+1]=temp
print(li)

 改进

li=[11,33,4,208,22,89,182,32,69,358,222]

for j in range(1,len(li)):#为外层循环次数
　　 issorted=True
    for i in range(len(li)-j):
        current_value=li[i]
        next_value=li[i+1]
        if current_value > next_value:
            temp=li[i]
            li[i]=li[i+1]
            li[i+1]=temp
            issorted=False
    if issorted:
       break 
print(li)

 

转载于:https://www.cnblogs.com/lvjygogo/p/8522438.html