greta一些简单实用的字符串匹配-优快云博客

本文提供了多个正则表达式匹配示例，包括整数、正整数、浮点数和字母等不同类型的字符串匹配，并展示了如何进行替换、计算出现次数及切分字符串等操作。

代码

#if 0//整数
    match_results results;
    tstring str("f34");
    rpattern pat("^[+|-]?\\d+\\d*$");
    match_results::backref_type br = pat.match(str, results);
    if (br.matched)
    {
        tcout << "match" << std::endl;
    }
    else
    {
        tcout << "not match" << std::endl;
    }
#endif

#if 0//正整数
    match_results results;
    tstring str("+323f444");
    rpattern pat("^[+]?\\d+\\d*$");
    match_results::backref_type br = pat.match(str, results);
    if (br.matched)
    {
        tcout << "match" << std::endl;
    }
    else
    {
        tcout << "not match" << std::endl;
    }
#endif

#if 0//浮点数
    match_results results;
    tstring str("-3.23444");
    rpattern pat("^[+|-]?[0-9]+\\.?[0-9]+$");//^\-?[0-9]*\.?[0-9]*$
    match_results::backref_type br = pat.match(str, results);
    if (br.matched)
    {
        tcout << "match" << std::endl;
    }
    else
    {
        tcout << "not match" << std::endl;
    }
#endif

#if 0//字母
    match_results results;
    tstring str(".asdf");
    rpattern pat("^[a-z]*$");//^\-?[0-9]*\.?[0-9]*$
    match_results::backref_type br = pat.match(str, results);
    if (br.matched)
    {
        tcout << "match" << std::endl;
    }
    else
    {
        tcout << "not match" << std::endl;
    }
#endif

其他一些实用代码

代码

#if 1//subsitute 替换
    subst_results results;
    tstring str("a43sdf");
    REGEX_FLAGS dw = GLOBAL | NOCASE;
    rpattern pat("[0-9]","d",dw);
    int cnts = pat.substitute(str,results);

    subst_results::backref_vector vec = results.all_backrefs();
    subst_results::backref_vector::iterator iter;
    std::string m_strResult = "";
    for( iter = vec.begin(); iter != vec.end(); iter++ )
    {
        string _str = (*iter).str();
        m_strResult += _str.c_str();
    }

#endif

#if 0//count 计算正则表达式在串中出现的次数
    tstring str("asdf");
    rpattern pat("[a-z]");
    int cnts = pat.count(str);

#endif

#if 0//split 用正则表达式作为分隔符来切分串
    split_results results;
    tstring str("asdf");
    rpattern pat("[a-z]");
    int cnts = pat.split(str, results);

#endif

转载于:https://www.cnblogs.com/lancidie/archive/2011/02/09/1950222.html